pls help

Find all real numbers that satisfy the equation: $\frac{1}{r^3+7}-7=\frac{-r^3}{r^3+7}$.

$\frac{1}{r^3+7}-7=\frac{-r^3}{r^3+7}\\ \frac{1}{r^3+7}-\frac{-r^3}{r^3+7}=7\\ \frac{1+r^3}{r^3+7}=7\\ 1+r^3=7r^3+49\\ 6r^3=-48\\ r^3=-8\\ r=\boxed{-2}$

I hope this helped,

Gavin

it helped! thx! NOW IMA GLEAN YA(joke. just read sythe. it's awesome.!)