The trapezoid shown has a height of length $12\text{ cm},$ a base of length $16\text{ cm},$ and an area of $162\text{ cm}^2.$ What is the perimeter of the trapezoid?
Tysm in advance!!! I really need help... I don't think my teacher said enough, and it's not office hours. Thanks so so much!!!
+2401 I'd love to help.
b_1 = 16
b_2 = x
h = 12
a = 162.
The area of a trapazoid is the average of the bases * height.
(b_1+b_2)/2*h = a
(16+x)/2*12 = 162
16+x = 27
x = 11
So now we know the 2 bases.
For sake of simplicity, we'll just make the trapazoid look like a rectnagle with a triangle at the end.
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Should look smth like that.
We know 3 of the sides alr, the height and the 2 bases, and we can use the pythagreon theorum. 5^2+12^2 = 13^2.
So our sides are 13 + 11 + 16 + 12 = 52
I hope this helped. :))
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