Given that 2^x=7, find the value of 4(x - 1).
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\(2^x=7\\ x\cdot ln\ 2=ln\ 7\\ x=\dfrac{ln\ 7}{ln\ 2}\)
\(4(x - 1 )=4\cdot (\dfrac{ln\ 7}{ln\ 2}-1)\)
\( 4(x - 1)=7.229...\)
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