There are 50 animals on the farm. There are 30 cows on a farm and a number of chickens and horses. When the farmer trades away as many cows as there are horses, there are an equal number of cows to chickens and horses. Now how many cows, chickens, and horses are there?
Let the number of cows = 30
Let the number of chickens = x
Let the number of horses = 50 - 30 - x = 20 - x
When he trades away as many cows as horses he has 30 - (20- x) = 10 + x cows left
So
10 + x = x + (20 - x)
10 + x = 20
x =10
So he now has 10 + x = 10 + 10 = 20 cows left
And the number of chickens and horses = x + 20 - x = 10 + 20 - 10 = 20
And the number of cows = the number of chickens and horses