Suppose that a and b are digits in base d > 6 such that \(\overline{AB}_d+\overline{AA}_d=162_d\).
Find \(A_d-B_d\) in base d.
Thanks in advance!
72_8 + 77_8 = 162_8
7_8 - 2_8 = 5_8
Note: The first base I tried was base 8. I converted 162_8 to base 10 = 114. Then I tried 2 numbers that add up to 93. I tried 45 + 48 = 93. Then I converted 45 to base 7 =63. And similarly, converted 48 to base 7 = 66. Then added 72 + 77 (base 8) =162_8. That is how I arrived at the answer above.
