In which quadrant(s) do the graphs of y=x^2 and y=3x+10 intersect?
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\(y=x^2=3x+10\\ x^2=3x+10\\ x^2-3x-10=0\\ x=1.5\pm \sqrt{2.25+10}\\ x\in \{-2,5\}\\ y\ \in\ \{\ 4,25\}\)
They intersect in quadrants I and II.
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