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How do I do 1.25=(1+0.04)^x? And find x

Guest Mar 27, 2017
 #1
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x = ~5.6

just by guess and check... if you want a better answer use mathpapa.com

Guest Mar 27, 2017
 #2
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Take logs of both sides:

 

ln(1.25) = ln(1.04x)    

 

Use the following property of logs:  ln(ab) = b*ln(a) to get:

 

ln(1.25) = x*ln(1.04)

 

Divide both sides by ln(1.04)

 

x = ln(1.25)/ln(1.04) ≈ 5.689

.

Alan  Mar 27, 2017

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