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-1
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avatar+109 

Let\[p(x,y) = \begin{cases} x + y &\quad \text{if } x \ge 0 \text{ and } y \ge 0, \\ x - 2y &\quad \text{if } x < 0 \text{ and } y < 0, \\ 3x + y &\quad \text{otherwise}. \end{cases} \]What is $p(p(1,-1),p(-5,-2))$?

 Aug 29, 2020
 #1
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p(p(1,-1),p(-2,-5)) = -5.

 Aug 29, 2020

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