Pierre, Kelsey and Titus shared some magnets.

Pierre took 6 more than 1/4 of the magnets.

Kelsey took 2 more than 2/3 of the rest of the magnets.

Tituts took the last 12 magnets. How many magnets did Kelsey take?

Whayousayy Sep 15, 2021

#1**0 **

Let the number of magnets shared by the 3 boys==M

Pierre took ==1/4M + 6

M - [1/4M + 6]==3[M - 8]/4

Kelsey took ==[2/3 * 3[M - 8] / 4] + 2=[M - 4] / 2

1/4M + 6 + [M - 4] / 2 + 12 =M, solve for M

M==64 - Total number of magnets.

**Pierre took ==1/4*64 + 6 ==22 magnets. Kelsey took ==[64 - 4] / 2 ==30 magnets. Titus took ==12 magnets 22 + 30 + 12 ==64 magnets shared by 3 boys.**

Guest Sep 15, 2021

#2**0 **

Let initial no. of magnets = 12m.

1/4 of total : 3m

Remainder after Pierre : 12m - 3m - 6

= 9m - 6

2/3 of remainder : 2/3 * (9m - 6)

= 6m - 4

Remainder after Kelsey : 9m - 6 - (6m - 4) - 2

= 3m - 4

Since 12 magnets remain, 3m - 4 = 12

3m = 16

12m = 16 + 4

= 64

Kelsey took 6m-4+2

=6m-2

6m = 12m/2 = 32

6m-2 = 32-2 = __30__

DoctorOcopisMonOct Sep 15, 2021