+176 Pierre, Kelsey and Titus shared some magnets.
Pierre took 6 more than 1/4 of the magnets.
Kelsey took 2 more than 2/3 of the rest of the magnets.
Tituts took the last 12 magnets. How many magnets did Kelsey take?
Let the number of magnets shared by the 3 boys==M
Pierre took ==1/4M + 6
M - [1/4M + 6]==3[M - 8]/4
Kelsey took ==[2/3 * 3[M - 8] / 4] + 2=[M - 4] / 2
1/4M + 6 + [M - 4] / 2 + 12 =M, solve for M
M==64 - Total number of magnets.
Pierre took ==1/4*64 + 6 ==22 magnets.
Kelsey took ==[64 - 4] / 2 ==30 magnets.
Titus took ==12 magnets
22 + 30 + 12 ==64 magnets shared by 3 boys.
+80 Let initial no. of magnets = 12m.
1/4 of total : 3m
Remainder after Pierre : 12m - 3m - 6
= 9m - 6
2/3 of remainder : 2/3 * (9m - 6)
= 6m - 4
Remainder after Kelsey : 9m - 6 - (6m - 4) - 2
= 3m - 4
Since 12 magnets remain, 3m - 4 = 12
3m = 16
12m = 16 + 4
= 64
Kelsey took 6m-4+2
=6m-2
6m = 12m/2 = 32
6m-2 = 32-2 = 30
