1. Find a if the point (3,a) is on the line that passes through (-2,7) and (5,-3).
2.A line has the equation y=-2x/3 and passes through the point (2, -3) write the equation for the line in standard form.
3. Let line L_1 be the graph of 5x + 8y = -9. Line L_2 is perpendicular to line L_1 and passes through the point (10,10). If line L_2 is the graph of the equation y=mx +b, then find m+b.
x = 3 is between -2 and 5 5 /7 of the way between (moving from 2 to 5)
for y find 5/7 of the way between 7 and -3 a change of -10 5/7 (-10) + 7 = - 1/7
A line has the equation y=-2x/3 and passes through the point (2, -3)
this line does not pass through 2,-3
change y = -2/3 x into ax + by = c form
3y = -2x
2x+ 3y = 0
Here is another line THAT DOES pass thru 2,-3 and has SLOPE = - 2/3
y = -2/3 x + b sub in the given point
-3 = -2/3 (2) + b
b = -5/3
y = -2/3 x - 5/3
2x + 3y = -5
