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If $\sqrt{2\sqrt{t-2}} = \sqrt[4]{7 - t}$, then find $t$. 

 Feb 9, 2022
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\(\sqrt{2\sqrt{t-2}} = \sqrt[4]{7 - t}\)

 

First I multiplied both sides of the equation by ^4.

 

4(t-2) = 7 - t

 

4t - 8 = 7 - t

 

t = 3.

 Feb 9, 2022

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