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Let  r and s be the roots of \(3x^2+4x-12=0\) . Find \(r^2+s^2\)

 

Notice: This problem is similar to a previously asked question (https://web2.0calc.com/questions/help-help-asap-please) but the equations are slightly different. I have already checked so no need to get on my case about it. 

 Dec 6, 2022
 #1
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By the quadratic formula, the roots are \(\frac{-2 \pm \sqrt{43}}{3}\)

 

So \(r^2 + s^2 = \left( \dfrac{-2 - \sqrt{43}}{3} \right)^2 + \left( \dfrac{-2 + \sqrt{43}}{3} \right)^2 = \dfrac{94}{9}\)

 Dec 6, 2022
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Its not right; someone else please help!

Keihaku  Dec 6, 2022

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