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(7x+yi)+(11i+5)=1+i

 Sep 23, 2016
 #1
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(7x+yi)+(11i+5)=1+i

 

7x+yi+10i+4=0

 

What do you want me to do with this?

 

yi=-7x-10i-4

 

I suppose I could make y the subject - not that there is any great reason to do this.

 

\(y=\frac{-7x-10i-4}{i}\\ y=\frac{-7x-10i-4}{i}\times \frac{i}{i}\\ y=\frac{-7xi-10i*i-4i}{-1}\\ y=7xi-10+4i\\ y=-10+(7x+4)i\\\)

 Sep 23, 2016

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