The function f(n) = 3f(n-2) - 2f(n-1) , where f(2) = 3 and f(1) = -1 . What is the value of f(5) ?
Plug 5 into the equation:
f(5)=3f(5−2)−2f(5−1)
f(5)=3f(3)−2f(4)
f(3)=3f(1)−2f(2)
f(3)=−3−6
f(3)=−9
f(4)=3f(2)−2f(3)
f(4)=9+18
f(4)=27
f(5)=−27−54
f(5)=−81