pls help thank u!
Sicne FR has the same length as FG, arc RG is equal to arc FG. Then arc RG is 130, so angle RPG is equal to (130 - 28)/2 = 51 degrees.
sorry that is wrong D:
∠GOR = 100º consequently ∠GFR = 50º ( ∠GFR = ∠GFP )
∠FOQ = 28º consequently ∠FGQ = 14º ( ∠FGQ = ∠FGP )
(∠GFP) + (∠FGP) = ∠RPG = 64º
