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Neil and Chris were trying to solve the quadratic equation x^2 + bx + c = 0. Neil wrote down the wrong value of b (but his value of c was correct), and found the roots to be 1 and 6. Chris wrote down the wrong value of c (but his value of b was correct), and found the roots to be -1 and -4. What are the actual roots of x^2 + bx + c = 0?

 

(all the answers i got were wrong...)

 Mar 13, 2020
 #1
avatar+26006 
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WHY is this posted THREE TIMES!?

 Mar 13, 2020
 #2
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See https://web2.0calc.com/questions/pls-help_96

 Mar 13, 2020
 #3
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BECAUSE NO ONE CAN SEEM TO GET THE RIGHT ANSWER!!!

Guest Mar 13, 2020
 #5
avatar+110175 
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If no one gets the right answer why didn't you say so, on the original post.

AND also say why you believe it is not the right answer.

 

Is it because you are an ungrateful, uncommunicative brat?

Melody  Mar 14, 2020
 #4
avatar+21955 
+1

Neil's roots were 1 and 6 --->  (x - 1)(x - 6)  =  0   --->   x2 - 7x + 6  =  0   --->   c = 6

 

Chris' roots were -1 and -4   --->   (x + 1)(x + 4)  =  0   --->   x2 + 5x + 4  =  0   --->   b = 5

 

x2 + 5x + 6  =  0   --->   (x + 3)(x + 2)  =  0   --->   x = -3   or   x = -2

 Mar 14, 2020

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