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# plsplsplsplsplsss help im desperateeee

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Kana earns \$25,000dollar salary in the first year of her career. Each year, she gets a 4 percent raise. How much does Kana earn in the first 10 years of her career?

Jun 12, 2019
edited by ProffesorNobody  Jun 12, 2019

#1
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If your desperate ytou should start getting familar with the math lesson and text book and try a little reading for a change how I would do it is divide the value by 100 and the quiotient of that is equal to 1 percent.... the multiply it by four and add that that going up every year like this....

1 year \$25,000

2 year \$25,000 + 4%

3 year \$25,000 + 4% + 4%

4 year \$25,000 + 4% + 4% + 4%

5 year  \$25,000 + 4% + 4% + 4% +4%

6 year \$25,000 + 4% + 4% + 4% +4% + 4%

7 year \$25,000 + 4% + 4% + 4% +4% + 4% + 4%

8 year \$25,000 + 4% + 4% + 4% +4% + 4% + 4% + 4%

9 year \$25,000 + 4% + 4% + 4% +4% + 4% + 4% + 4% + 4%

10 year \$25,000 + 4% + 4% + 4% +4% + 4% + 4% + 4% + 4% + 4%

Jun 12, 2019
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but the 4% changes per year no? im confused

ProffesorNobody  Jun 12, 2019
edited by ProffesorNobody  Jun 12, 2019
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We add 4% every year so then you could say the second year add the original value and 8% of the orignal value

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??????????

ProffesorNobody  Jun 12, 2019
edited by ProffesorNobody  Jun 12, 2019
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no it changes...... like the second year you add 1000 and the next 1040...

ProffesorNobody  Jun 12, 2019
edited by ProffesorNobody  Jun 12, 2019
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Let me explain myself once you divide this orignal value by 100

it equals 250 so 250 times 4 = 100 you add 1000 to the original value the first year btut he percent raises every year so the next year she's going ot get 2000 more like this...

25,000 + 1000

25,000 + 2000

see how this translates to 25,000 + 4% and 25,000 + 4% +4% ?

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We have a sum of a geometric series

The sum =     Initial Amt [ 1 - common ratio ^n ] / [ 1 - common ratio ]

Intial amt  = 25000

Common ratio  = 1 + 4%  =  1.04

n = 10  (years)

So

Total  =

25000 [  1 - 1.04^10] / [ 1 -1.04]   ≈ \$300,152.68

Jun 12, 2019
edited by CPhill  Jun 12, 2019
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thank you

ProffesorNobody  Jun 13, 2019