We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
-3
70
4
avatar+25 

A right triangle has leg lengths of 7 and 24 units. A second triangle is similar to the first triangle and has a hypotenuse of 100 units. What is the length, in units, of the shorter leg of the second triangle?

 Jun 9, 2019
 #1
avatar+107 
+2

By the pathogorean theorum, the hypotonuse of the first triangle is \(\sqrt{7^2+24^2} = 25\)

Because the two triangles are similar, the rario between the side lengths will be the same on both triangles.

\(\frac{100}{short leg}=\frac{25}{7}\) 

cross multiply

700=25*short leg

divide by 25

short leg of the second triangle=\(\boxed{28}\)

.
 Jun 10, 2019
 #3
avatar+25 
-5

THX OMG I NEEEEEDED THAT

ProffesorNobody  Jun 10, 2019
 #2
avatar+90 
+2

ratio of your first triangle is 7-24-25 (it's a pythagorean triple, you could also find 25 using pythagoreon thereom) 

ratio of bigger tirangle is x:x:100. To get from 25 to 100, x4. 7 x 4 = 28, 24 x 4 = 96

The ratio of your bigger triangle is 28 : 96 : 100

The shorter leg value of the second triangle is 28

 Jun 10, 2019
 #4
avatar+25 
-5

THX OMG I NEEEEEDED THAT

ProffesorNobody  Jun 10, 2019

17 Online Users

avatar