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# PLSS HELP ME

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If  $$y=kx^{\frac{1}{4}}$$and $$y=3\sqrt{2}$$ at $$x=81$$, what is the value of $$y$$ at $$x=4$$?

Jun 14, 2022

#1
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When x is equal to 4, y = 4.

Jun 14, 2022
#2
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im sorry but its wrong

Guest Jun 14, 2022
#3
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Substitute (x, y) = (81, 3 sqrt(2)).

$$3\sqrt 2 = k \cdot 81^{1/4}\\ k = \sqrt 2$$

Then, substitute k = sqrt(2) and x = 4.

$$y = \sqrt 2 \cdot 4^{1/4} = 2$$

Jun 15, 2022