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If  \(y=kx^{\frac{1}{4}}\)and \(y=3\sqrt{2}\) at \(x=81\), what is the value of \(y\) at \(x=4\)?

 Jun 14, 2022
 #1
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When x is equal to 4, y = 4.

 Jun 14, 2022
 #2
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im sorry but its wrong

Guest Jun 14, 2022
 #3
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Substitute (x, y) = (81, 3 sqrt(2)).

 

\(3\sqrt 2 = k \cdot 81^{1/4}\\ k = \sqrt 2\)

 

Then, substitute k = sqrt(2) and x = 4.

\(y = \sqrt 2 \cdot 4^{1/4} = 2\)

 Jun 15, 2022

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