If \(y=kx^{\frac{1}{4}}\)and \(y=3\sqrt{2}\) at \(x=81\), what is the value of \(y\) at \(x=4\)?
When x is equal to 4, y = 4.
im sorry but its wrong
Substitute (x, y) = (81, 3 sqrt(2)).
\(3\sqrt 2 = k \cdot 81^{1/4}\\ k = \sqrt 2\)
Then, substitute k = sqrt(2) and x = 4.
\(y = \sqrt 2 \cdot 4^{1/4} = 2\)
