Suppose that \(a\) is a nonzero constant for which the equation \(ax^2+20x+7=0\) has only one solution. Find this solution.
The determinat of the quadratic formula must = 0 for only one solution to the equation
b^2 - 4ac = 0
20^2 - 4(a)(7) = 0 solve for 'a' ........... you can finish, right?