If we express \(3x^2 - 6x - 2\) in the form \(a(x - h)^2 + k\), then what is \(a + h + k\)?
3 ( x^2 - 2x - 2/3) complete the square inside the parentheses
Take 1/2 of 2 = 1.....square it =1....add and subtract it
3( x^2 - 2x + 1 - 2/3 - 1) factor the first three terms in the patrntheses, simplify the rest
3 [ ( x - 1)^2 - 5/3 ]
3( x - 1)^2 - 5
a + h + k = 3 + 1 - 5 = -1