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i want to plot θ against β

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°

 Aug 21, 2015

Best Answer 

 #3
avatar+33616 
+10

Here's a 3d plot of the function (in blue) on the left-hand side of the equation, showing where it intersects with the zero plane (in grey).  There is also a 2D plot showing the lines of theta vs beta on the zero plane.  The axes are in radians (0 to pi/2 for both theta and beta).

. 3D and 2D plots

.

 Aug 21, 2015
 #1
avatar+26367 
+10

Sin(θ-β)-2sin(2(θ-β))-sin(2θ)=0

0°<​θ<90°

0°<β<90°

 

wolframalpha:

plot sin(y-x)-2sin(2(y-x))-sin(2y) = 0 ( 0<x<pi/2 ) (0<y<pi/2)

http://www.wolframalpha.com/input/?i=plot+sin%28y-x%29-2sin%282%28y-x%29%29-sin%282y%29+%3D+0+%28+0%3Cx%3Cpi%2F2+%29+%280%3Cy%3Cpi%2F2%29

 

 Aug 21, 2015
 #2
avatar+128577 
0

.............

.
 Aug 21, 2015
 #3
avatar+33616 
+10
Best Answer

Here's a 3d plot of the function (in blue) on the left-hand side of the equation, showing where it intersects with the zero plane (in grey).  There is also a 2D plot showing the lines of theta vs beta on the zero plane.  The axes are in radians (0 to pi/2 for both theta and beta).

. 3D and 2D plots

.

Alan Aug 21, 2015

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