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A ball travels on a parabolic path in which the height (in feet) is given by the expression -25t^2+75t+24, where t is the time after launch. At what time is the height of the ball at its maximum?

 Apr 4, 2020
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Maximum will occur at    t =      -b/2a        a = -25    b = 75 

-b/2a   =  75/50 =   1  1/2 sec

 Apr 4, 2020

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