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Find the product of all positive integral values of n such that \(n^2-35n+306=p\) for some prime number p. Note that there is at least one such n.

 Oct 21, 2020
 #1
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For n = 16  and  19,  n^2-35n+306=2 - the smallest prime

 

Their product =16  x  19 =304

 Oct 21, 2020
edited by Guest  Oct 21, 2020
 #2
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Thanks guest! You were right! Thanks for the help!smiley

Guest Oct 21, 2020

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