What is the positive difference of the solutions of \(\dfrac{r^2-3r-17}{r+4}=2r+7\) ?
Help, I'm stuck on this problem.
Thanks!
Multiply both sides of the equation by r+4 to get
r^2 -3r-17 = 2r^2 +15r + 28 simplify
r^2 +18r + 45 = 0
(r+15)(r+3) = 0 You should be able to finish......