help me solve this please i dont know where to start\(\[25^{-2}= \frac{5^{48/x}}{5^{26/x}\cdot 25^{17/x}}.\]\)
Let t = 1/x.
\(25^{-2} = \dfrac{5^{48t}}{5^{26t} \cdot 25^{17t}}\)
Rewrite 25^n into 5^(2n),
\(5^{-4} = \dfrac{5^{48t}}{5^{26t}\cdot 5^{34t}}\)
By law of indices,
\(5^{-4}= 5^{-12t}\)
Equating the powers would give t = 1/3, which means x = 3.
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