Problem 1) PQ is similar to AB because of Side-Angle-Side. P and Q lie on sides AO and OB respectively, and \(\angle POQ = \angle AOB\).
Problem 2) Because \(OP = {3 \over 5} \times AO\), we know that \(OP = {3 \over 5} \times 10 = \color{brown}\boxed{6}\)