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Find the area of an isosceles triangle with two legs of length 8 and base of length 6.

 Apr 22, 2021
 #1
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The  height  is   sqrt  (8^2  -  (6/2)^2 )  = sqrt [  64  - 3^2) = sqrt (55)

 

Area =  (1/2)  base length *  height =    (1/2) (6) sqrt (55)  =  3 sqrt (55) units^2  ≈ 22.25  units^2

 

 

cool cool cool

 Apr 22, 2021
 #2
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THX UR CORRECT!!! cool

Guest Apr 22, 2021

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