Find the area of an isosceles triangle with two legs of length 8 and base of length 6.
The height is sqrt (8^2 - (6/2)^2 ) = sqrt [ 64 - 3^2) = sqrt (55)
Area = (1/2) base length * height = (1/2) (6) sqrt (55) = 3 sqrt (55) units^2 ≈ 22.25 units^2
THX UR CORRECT!!!
