Triangle ABC is isosceles with AB = BC. If AC = 20 and [ABC] = 240, then find the perimeter of triangle ABC. Solve using Heron's Formula.
first of all, i also dont understand who heron is.
but idc about heron, I can solve it without heron
look dude, we are gonna get the perimeter by this:
sorry i did not have any geometrical materials, hope u dont think its a slice of pizza!
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Let AB = BC = x
The semi-perimeter = ( 2x + 20) / 2 = x + 10 = s
Area^2 = s ( s - x) ( s - x) ( s - 20)
240^2 = (x + 10) ( 10) ( 10) (x - 10)
240^2 = 100 ( x^2 - 100)
240^2 /100 = x^2 - 100
576 = x^2 - 100
676 = x^2 take the positive root
26 = x
The perimeter = 2x + 20 = 2(26) + 20 = 52 + 20 = 72