Find the smallest real value of $x$ such that $x^2+6x + 9 = 24$.
x^2 + 6x + 9 = 24 can be written as x^2 + 6x - 15. If we plug in the quadratic formula, we get -3+- sqrt(24). But since it's the smallest real value of x, it's really the minus sign so the real answer is -3 - sqrt(24)