plz help me i want to understand this

 2(x-3)(x^2+1)=0 help.. :,(

=2x^3 - 6x^2 + 2x - 6 = 0

zero mutiplied by smthing will give you zero :)

So you need to find how can you make a zero:

2(x-3)(x^2+1)=0

x-3=0                                                           x^2+1=0

x=3                                                               x^2=-1

                                           since square CAN NOT be negative so that one is WRONG

Answer: x=3