plz help!
2x+3y=6 (for x)
Fm-3=Q (for F)
in order to solve for x just pretend 3y doesn't exist. block it out. then you just have 2x=6. from there it's a simple one-step equation. x=3
for F you would first add three making the equation Fm=Q+3 then divide by M making the equation F=Q+3 over M
Subtract 3 from both sides
2x = 6 - 3y divide both sides by 2
x = [ 6 - 3y ] / 2
Fm-3=Q (for F) → F = [Q + 3] / m
