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A hat contains four balls. The balls are numbered 2, 4, 4, and 5. One ball is randomly selected and not replaced, and then a second ball is selected. The numbers on the two balls are added together.

A fair decision is to be made about which of three sizes of ice cream cone will be ordered, using the sum of the numbers on the balls. The sizes are small, medium and large.

Which description accurately explains how a fair decision can be made in this situation?

If the sum is 6, a small cone will be ordered.
If the sum is 7 or 8, a medium cone will be ordered.
If the sum is 9, a large cone will be ordered.

 

If the sum is 6 or 7, a small cone will be ordered.
If the sum is 8, a medium cone will be ordered.
If the sum is 9, a large cone will be ordered.

 

If the sum is 6, a small cone will be ordered.
If the sum is 7 or 9, a medium cone will be ordered.
If the sum is 8, a large cone will be ordered.

 

If the sum is 6 or 9, a small cone will be ordered.
If the sum is 7, a medium cone will be ordered.
If the sum is 8, a large cone will be ordered.

 Apr 2, 2020
 #1
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Since two of the balls have the number 4, I'm going to call them 41 and 42.

This means, that there are these four balls:  2, 41, 42, and 5.

 

Possibilities:

   2 + 41  =  6        41 + 2   =  6          42 + 2  =  6          5 + 2    =  7

   2 + 42  =  6        41 + 42  =  8         42 + 41  =  8         5 + 41  =  9

   2 + 5    =  7       41 + 5    =  9         42 + 5    =  9         5 + 42  =  9

 

There are 4 ways to get a total of 6.

There are 2 ways to get a total of 7.

There are 2 ways to get a total of 8.

There are 4 ways to get a total of 9.

 

Can you finish the problem?

 Apr 2, 2020

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