+129852 This one is a litle tricky, RP
x^2 - 12 x + 49 = 22 subtract 22 from both sides
x^2 - 12x + 27 = 0 we need two numbers that su to -12 and multiply to 27...-9 and -3 fit the bill...so we have
(x - 9) ( x - 3) = 0
Setting these to 0 and solving for x produces x = 9 and x = 3
Look at "A"
If x = 9, we have (9- 6)^2 = 3^2 = 9
And if x = 3 , we have (3-6)^2 = (-3)^2 = 9
So....that must be the correct one !!!!
Does that make any sense.....???
Another way to do this is to expand each answer....note that
(x - 6)^2 = 9 becomes
(x - 6) ( x - 6) = 9
x^2 - 12x + 36 = 9
x^2 - 12x + 27 = 0 which is the same equation we found initially (in red, above)....so....they must have the same solutions !!!
