What real value of t produces the smallest value of the quadratic t^2 - 8t - 36?
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\(f(t)=t^2 - 8t - 36\\ \frac{df(t)}{dt}=2t-8=0\)
\(t=4\)
\(t=4\ produces\ the\ smallest\ value\ of\ the\ quadratic\ t^2 - 8t - 36.\)
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