For what real values of c is \( 4x^2 + 14x + c\) the square of a binomial?
The discriminant \(b^2 - 4ac\) must be 0. So we have the equation \(196 -4c = 0\), and we need to solve for c.
Can you take it from here?
Here's another way:
(Incidentally, you should check your result for b^2 - 4ac BuilderBoi).
+2668 
