In the diagram below, A is on line segment CE and AB bisects Angle DAC. If segment DA is parallel to segment EF and angle AEF = 10angleBAC - 22 degrees, then what is angle DAC in degrees?
Extend F thru E to G
Angle GEC is supplemental to angle AEF
So GEC = 180 - ( 10BAC - 22) = 202 - 10BAC = angle DAC
And BAC = (1/2)DAC
So
202 - 10 (1/2)DAC = DAC
202 - 5DAC = DAC
202 = 6DAC
DAC = 202 / 6 ≈ 33.66°
Oops!!! I made boo-boo
