The quadratic $x^2-3x+1$ can be written in the form $(x+b)^2+c$, where $b$ and $c$ are constants. What is $b+c$?
x^2-3x+1
x^2 -3x +2.25 - 2.25 +1
(x-1.5)2 -1.25 b = -1.5 c= -1.25 b+c =..........