In the diagram below, we have line AB is parallel to line CD, EF = FG, < BEF = 130 degrees + x degrees, and < AEG = x degrees. Find the value of x.
Angle AEG = angle EGF = x
And because EF = FG , then angles EGF and GEF are equal = x
So
angle BEF + angle GEF + angle AEG = 180
130 + x + x + x = 180
3x + 130 = 180
3x =180 -130
3x = 50
x = (50/3)° = (16 + 2/3)°
