+129839 6a The volume will consist of that of a cylinder with a height of 17m and a radius of (22 - 17) = 5m plus the volume of a hemisphere with a radius of 5m.....so we have
pi * (5^2) * 17 + (2/3)pi * 5^3 = about 1596.98 m^3
The surface area of the two objects =
2pi (5)(17) + 2pi *5^2 = about 691.15 m^2
6b We have a rectangular solid and a cone........the volume =
7*5*9 + pi (2^2)*6/3 = about 340.13 cm^3
The surface area =
2 [5*9 + 9*7 + 5*7] + pi *(2)sqrt(6^2 + 2^2) = 286 + 39.74 = about 325.74 cm^2
