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Suppose that \(x,y,z\) are positive integers satisfying \(x \le y \le z\), and such that the product of all three numbers is twice their sum. What is the sum of all possible values of \(z\)?

 

BTW, the answer is not 507.

 Jun 3, 2020
 #1
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The sum of all possible vaues of z is 2 + 3 + 4 + 6 = 15.

 Jun 3, 2020
 #2
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What is wrong with these numbers?
x        y        z
1        3        8
1         4       5
2         2       4
z =8 + 5 + 4 = 17

 Jun 3, 2020

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