+0  
 
0
100
4
avatar+236 

My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. For how many minutes will my friend have been walking when I catch up to her?

 Jan 14, 2021

Best Answer 

 #1
avatar
+2

You need to cover the 1/4 mile head start.....you are walking 1 m/hr faster than your friend    1/4 m  /  1 m/hr = 1/4 hr = 15 minutes to catch

 Jan 14, 2021
 #1
avatar
+2
Best Answer

You need to cover the 1/4 mile head start.....you are walking 1 m/hr faster than your friend    1/4 m  /  1 m/hr = 1/4 hr = 15 minutes to catch

Guest Jan 14, 2021
 #3
avatar
0

* * * edit * * *

 

    it will take you 15 minutes to catch your friend.....who will have been walking for   20 minutes

Guest Jan 14, 2021
 #2
avatar+303 
+1

I got my answer form here: https://web2.0calc.com/questions/my-friend-any-help-is-appreciated

This answer is from CPhill:

At 3 mph....your friend covers  3 / 60   miles per minute

 

At 4 mph......you cover  4/ 60    miles per minute

 

So....every minute....you close    [  4 - 3 ]/ 60   =  1/ 60   miles  on your friend

 

And when she has been walking for 5 minutes......she will be  5 * [3  / 60 ]  = 15/60  = 1/4 of a mile ahead of you when you start 

 

So......the number of minutes, m, it will take to catch your friend can be found by :

 

( 1/60) m  = 1/4      multiply both sides by 60

 

m =  60  / 4   =    15 minutes

 Jan 14, 2021
 #4
avatar+11 
+1

Figure out how far you walk in one minut at 3 miles per hour and figure out how far you walk in a minute at 4 miles per hour and add the 3 miles to itself and the 4 miles to itself and then add how far you go in 1 minute for the three or the four to the three or the four total and repeat until you either pass your friend or catch up to her and if you pass her figure out how far you are from her and subtract that from where you are

 

I am sorry if this is not helpful. I try my best =>

 Jan 14, 2021

52 Online Users

avatar
avatar