I need help with this problem:
Let G be the centroid of triangle ABC. If triangle ABG is an equilateral triangle with a side length of 2, then find the area of triangle ABC.
Since G is the centroid of triangle ABC, we know that it is the intersection point of the medians of the triangle. A median divides a triangle into two smaller triangles of equal area. In this case, we have triangle ABG as one of those smaller triangles, and it's given that ABG is an equilateral triangle with side length 2.
The area of an equilateral triangle can be found using the formula:
Area = (side^2 * √3) / 4
For triangle ABG, we have:
Area(ABG) = (2^2 * √3) / 4 = 4√3 / 4 = √3
Since triangle ABC is composed of 3 smaller triangles with equal area (ABG, ACG, and BCG), we can find the area of triangle ABC by multiplying the area of triangle ABG by 3:
Area(ABC) = 3 * Area(ABG) = 3 * √3 = 3√3
So the area of triangle ABC is 3√3 square units.