- Given the points A(-3,-4) and B(5,0), find the coordinates of point P on the directed line segment
*AB*that partitions*AB*in the ration 2:3. - Given J(-2,5) and k(2,-3). Find the point P on JK such that 4•JP=PK.

Bleh674
Dec 6, 2018

#1**+1 **

Now this is something I can help with!

#1: The ratio 2:3=5 so you would use 2/5 or 3/5 as a fraction (I'll do 2/5 with this example)

Use the distance formula: [x1+a/a+b(x2-x1), y1+a/a+b(y2-y1)]

Plug in all the numbers and solve:

X: -3+2/5(5+3)=0.2

Y: -4+2/5(0+4)=-2.4

P= (0.2,-2.4)

Now #2 is a bit different but also the same.

The ratio would be 4:1. Four part JP and one part PK.

4:1=5 so your fraction would be either 4/5 or 1/5 (using 1/5 here)

X: -2+1/5(2+2)=-1.2

Y: 5+1/5(5+3)=6.6

P=(-1.2,6.6)

Tell me if you don't understand something from my explanation and I can try to help a little bit more.

RainbowPanda
Dec 6, 2018

#2**+1 **

Thank you so much! I think I understand, if I have any questions I'll make sure to ask.

Bleh674
Dec 6, 2018

#3**+1 **

You're very welcome! I'd love to help if you have anymore of these questions ^-^

RainbowPanda
Dec 6, 2018