the nmber of bacteria p(t) in a petri dish at time t minutes is modelled by p(t)1000(ln3)^t find the rate of growth of population of bacteria where there are 10000 bacteria in a dish

Guest Dec 27, 2022

#1**0 **

P(t) = 1,000 x (ln(3)^t). You already have "rate of growth, which is ln(3) =1.0986123 - 1 x 100=9.86123% p/m

I think what you want is: " How long does it take 1,000 bacteria to become 10,000?" if that is right, then:

10,000 = 1,000 x (ln3)^t, solve for t

10,000 / 1,000 = (ln3)^t

10 = (ln3)^t

t =ln(10) / ln (ln3)

**t=24.483 - minutes for 1,000 bacteria to grow to 10,000**

Guest Dec 27, 2022