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You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal all $12$ cards at random to four players, so that each player gets three cards. What is the probability that each player gets an Ace, a $2$, and a $3$?

 Aug 9, 2020
 #1
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Getting an ace would have a probability of 4/16, or 1/4.

 

When someone draws one, one is taken away.

 

The equation would be: 1/4 times 1/5 times 1/7 times 1/13 = 1/1820.

 Aug 9, 2020
 #2
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First Guest, I need a little more help.  Where did the 16 come from? 

Guest Aug 9, 2020
 #3
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Why didn't you present your post properly before you published it?

If our kind guest had not already answered I would have removed the question from the forum.

 Aug 10, 2020

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