+0  
 
0
93
1
avatar

Catherine rolls a standard 6-sided die six times.  If the product of her rolls is \(2500\) then how many different sequences of rolls could there have been?  (The order of the rolls matters.)

 Jun 15, 2023
 #1
avatar
0

There are 2 combinations only as follows:

 

145555 ==6! / 4! ==30 permutations

225555 ==6! / 4!2! ==15 permutations

 

Total ==30  +  15 ==45 different sequences of rolls.

 Jun 16, 2023

1 Online Users