1. In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is
born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability
that the family has 0, 1, or 2 girls.
Below is a tree diagram and binomial distribution table.
X 0 1 2
P X( ) (0.52 0.52 0.2704 )( ) =
(0.52)(0.48) = 0.2496
(0.48 0.48 0.2304 )( ) =
Is the tree diagram and binomial distribution table correct? If not, state and explain the mistake.
https://learning.k12.com/content/enforced/518567-COF_ID162535/Algebra%202%20Unit%204%20Edit.pdf?_&d2lSessionVal=H5aA6ifTnIKZq9a9nw7bj2piP
+6252 P[1]=(21)(0.48)(0.52)=2(0.48)(0.52)=0.4992The table at the link got this wrong by a factor of 2because they only accounted for one of the 2 paths to get to 1 girl/1 boy
.
+118703 My goodness you are a lazy guest. I hope you have to sit for an exam because you will almost certainly fail.
Sorry Rom but I answered this question ealier today and I requested that they did some of their own thinking and interact with me.
You did not know that, I am certainly not upset with you. I just get so annoyed/upset with all the askers here who have no desire to learn anything.
