We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

1. In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is
born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability
that the family has 0, 1, or 2 girls.
Below is a tree diagram and binomial distribution table.
X 0 1 2
P X( ) (0.52 0.52 0.2704 )( ) =
(0.52)(0.48) = 0.2496
(0.48 0.48 0.2304 )( ) =
Is the tree diagram and binomial distribution table correct? If not, state and explain the mistake.




 Mar 8, 2019

\(P[1] = \dbinom{2}{1}(0.48)(0.52) = 2 (0.48)(0.52) = 0.4992\\ \text{The table at the link got this wrong by a factor of 2}\\ \text{because they only accounted for one of the 2 paths to get to 1 girl/1 boy}\)

 Mar 8, 2019

Thank you!! <3 

Guest Mar 8, 2019

My goodness you are a lazy guest. I hope you have to sit for an exam because you will almost certainly fail.



Sorry Rom but I answered this question ealier today and I requested that they did some of their own thinking and interact with me.

You did not know that, I am certainly not upset with you.    I just get so annoyed/upset with all the askers here who have no desire to learn anything. 

 Mar 8, 2019

Sorry Melody I didn't know.

Rom  Mar 9, 2019

5 Online Users