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avatar+24 

Hi, I need help solving:

If \((x,y)\) satisfies the simultaneous equations\(\begin{align*} 3xy - 4x^2 - 36y + 48x &= 0, \\ x^2 - 2y^2 &= 16, \end{align*}\)

where x and y may be complex numbers, determine all possible values of y^2.

 
 Nov 20, 2024
 #2
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Hi there!

 

I found the solutions y = -4 and y = 4, so the only possible value of y^2 = 16.

 

Hope this helps!

 Nov 21, 2024

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