+36 Hi, I need help solving:
If (x,y) satisfies the simultaneous equations3xy−4x2−36y+48x=0,x2−2y2=16,
where x and y may be complex numbers, determine all possible values of y^2.
+1208 Hi there!
I found the solutions y = -4 and y = 4, so the only possible value of y^2 = 16.
Hope this helps!
