In the diagram below line segment AD is parallel to line segment BE and A is not on line segment BC. Line segments AD and BC intersect at P. Can angle CAD equal angle CBE?
Thank you for your help in advance!
Note that if AD is parallel to BE, then corresponding angles ADC and BEC are equal
Thus, in triangles CAD and CBE, angle ADC = angle BEC
But angle ACD > angle BCE
So
Then
ADC + ACD > BEC + BCE
And because all three angles in each triangle will sum to 180
Then angle CAD must be less than angle CBE